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Work Calculator

Calculate the work done when a force moves an object over a distance.

Built and verified by Jogeswar, MSc, PMP — Tool CornerMethod and figures checked against the sources listed below
Work done
{{ joules }}J
Kilojoules{{ kj }} kJ
Foot-pounds{{ ftlb }} ft·lb
Kilocalories{{ kcal }} kcal
Working

{{ working }}

  • {{ n.text }}

The angle is doing real damage here: 1,039 J against the 1,200 J a horizontal pull would have done is a 13.4% loss, and it all goes into pressing the crate against the floor rather than moving it along. Lower the rope angle and you recover it.

Next step

What next?

Work done over time is power. Work stored in motion is kinetic energy.

How to use this calculator

  1. Enter the force applied, in newtons.
  2. Enter the distance the object moves, in metres.
  3. Set the angle between the force and the direction of motion (0° if they line up).

What your result means

Work is energy transferred when a force moves something — measured in joules. Only the part of the force acting along the direction of motion does work, which is why the angle matters: push at 90° to the motion and no work is done.

Why this one is different

The angle between the force and the movement is part of the sum, not an afterthought, and its consequence is spelled out: at ninety degrees the cosine is zero, so carrying a bag along a level floor does no work at all. Past ninety the figure goes negative, because the force is now taking energy out of the motion, and that is labelled too.

Force vs work

Holding a heavy box does no work

In physics, work needs movement. Straining to hold a box still feels like effort, but with zero distance the work done is zero. Carry it across the room and you finally do measurable work — force multiplied by the distance travelled.

How it works

Work equals force times distance times the cosine of the angle between them. When force and motion point the same way (θ = 0°), cosθ = 1 and work is simply force × distance. At 90°, cosθ = 0 and no work is done.

Formula

W = F × d × cosθ

Worked example

Dragging a crate 8 m with a 150 N force applied at 30° to the floor:

W = F × d × cos θ
W = 150 × 8 × cos 30°
W = 150 × 8 × 0.8660
W = 1,039 J (about 1.04 kJ)

Pulling horizontally instead (θ = 0°) would do 1,200 J — the vertical component of an angled pull does no useful work along the floor.

Frequently asked questions

What are the units of work?

Work is measured in joules (J) in SI units. One joule is one newton of force moving something one metre. It is the same unit used for energy.

Why does the angle reduce the work?

Only the component of force along the direction of motion does work. At an angle, that component is F×cosθ, so the steeper the angle the less work is done — reaching zero at 90°.

Is work the same thing as energy?

They share a unit and, in this context, a value: work is energy transferred by a force. Doing 1,000 J of work on an object hands it 1,000 J of energy. The distinction is that energy is a quantity a system has, while work is the process of moving it from one place to another.

Why is no work done when I hold something still?

Because work requires displacement. Holding a heavy box is tiring because muscles consume energy maintaining tension, but in the mechanical sense nothing moves, so no work is done on the box.

How does work relate to power?

Power is work divided by the time taken. Lifting the same load up the same stairs does identical work whether you walk or run; running simply demands more power.

Does work depend on the path taken?

For conservative forces such as gravity, no: only the start and end heights matter. Against friction it very much does, which is why a longer route costs more energy even when it ends in the same place.

Related calculators

Assumptions & limitations

Engineering formulas are exact; the situations they model are not. Read your result with these limits in mind:

  • Assumes a constant force acting over the whole displacement. A varying force needs the integral of force with respect to distance.
  • Only the component of force along the direction of motion does work, which is what the cos θ term handles.
  • A force perpendicular to motion does zero work — carrying a box across level ground does no work on the box in the physics sense.
  • Ignores energy lost to friction and heat unless you enter the friction force yourself.

Further reading

This is a calculator, not an engineering design check

The result is a single textbook relationship applied to the numbers you typed. It assumes ideal materials, ideal geometry and the load case described in the assumptions above, and it applies no safety factor of any kind. Real design work has to satisfy the governing code for the country and application, with factored loads, material partial factors and a competent engineer signing it off. Never size a real member, circuit or pressure part from this page.

Definitions and units on this page follow the standards listed below. The page has not been reviewed by a chartered engineer. Read the full disclaimer.

Sources & references

The formula and units used here follow the standard definitions published by:

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